Question

How do you simplify `(3wy ^-2)/(w^-1y)^3`?

Answer 1

`(3wy ^-2)/(w^-1y)^color(blue)(3`

`=(3wy ^-2)/(w^(-1. color(blue)(3)) . y^ color(blue)(3)`

`=(3w^1y ^-2)/(w^(-3) . y^ (3)`

We know that `color(blue)(a^m/a^n = a^(m-n)`
Applying this to our expression:

`=(3) . w^((1+3)) . y ^((-2-3))`

`=3 w^4 y ^-5`