Question

How do you find the zeroes of `g(x)=2x^2-5x-3`?

Answer 1

`g(x) = 2x^2 -5x-3`can be factored as
`color(white)("XXXX")` `g(x)=(2x+1)(x-3)`

The zeroes of `g(x)` are the values of `x` for which `g(x)=0`

If `g(x) = (2x+1)(x-3) = 0` then
either
`color(white)("XXXX")` `2x+1 = 0 rArr x= -1/2`
or
`color(white)("XXXX")` `x-3 = 0 rArr x = 3`

So the zeros of `g(x)` are `(-1/2)` and `3`