How do you use factoring to solve this equation #3x^2/4=27#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Tessalsifi Jun 8, 2015 #27=3*9# Thus : #cancel3(x²)/4=cancel3*9# #(x²)/4=9# #x²=9*4# ( we multiply by 4 on each side ) #x²=36# Thus : #x=sqrt36# => #x=6# Or : #x=-sqrt36# => #x=-6# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1448 views around the world You can reuse this answer Creative Commons License