Question

Question #57654

Answer 1

About `"5 N"` [down the incline].

Explanation:

The force acting on the object is equal to the object's weight `mg`

On an incline, this force is divided into two components.

Component 1 directed into the incline = `mgcostheta`

This force is balanced by the normal force (the supporting force exerted by the incline on the object)

Component 2 is parallel to the incline = `mgsintheta`

This is the unbalanced (net force) on the object--take `g = "10 m s"^(-2)`

`F_"net"=mgsintheta =(2)(g)5/20 = "5 N"`