Question

How do you find the intercepts for `f(x) = 4/5x + 7`?

Answer 1

That's when set you `x=0 orf(x)=y=0`

Explanation:

`y`-intercept:
`x=0->f(x)=7->(0,7)`

`x`-intercept:
`f(x)=0->4/5x+7=0->4/5x=-7->`

`x=-7/(4/5)=-35/4=-8 3/4->(-8 3/4,0)`
graph{0.8x+7 [-14.545, 5.455, -1.96, 8.04]}