Question

How do you solve the equation and identify any extraneous solutions for `1/(x-1) + 4/(4x-4) = 2`?

Answer 1

Extraneous would be if one of the numerator would be `=0`
In both fractions that means `x!=1`

Explanation:

We can divide top and bottom of the second fraction by `4`:
`1/(x-1)+1/(x-1)=2/(x-1)=2->`

`1/(x-1)=1->x-1=1->x=2`

And this is allowed.