Question

How do you solve `3x^2 + 7x - 6 = 0`?

Answer 1

You get two solutions:
`x_1=2/3`
`x_2=-3`

Explanation:

You can use the Quadratic Formula: `x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`;
Your equation is in the form:
`ax^2+bx+c=0`
Where:
`a=3`
`b=7`
`c=-6`
so, using these values into the Quadratic Formula you get:
`x_(1,2)=(-7+-sqrt(49+72))/6=(-7+-11)/6=`
you get two solutions:
`x_1=2/3`
`x_2=-3`