Question

How do you solve `2/3(a-3)=1/3`?

Answer 1

`a = 7/2`

Explanation:

First we need to "delete" `2/3` by multiplying both side by the inverse of `2/3 => (2/3)^-1=3/2`

`=>a-3=1/2`

and then add `3` both side

`=>a = 1/2 + 3 = 7/2`

Finally we have

`a = 7/2`