Question

How do you find the derivative using the Quotient rule for `f(z)= (z^2+1)/(sqrtz)`?

Answer 1

`y'=(3z^2-1)/(2zsqrtz)`.

Explanation:

In this way:

`y'=(2z*sqrtz-(z^2+1)*1/(2sqrtz))/(sqrtz)^2=`

`=((2z*sqrtz*2sqrtz-z^2-1)/(2sqrtz))/z=(4z^2-z^2-1)/(2zsqrtz)=`

`=(3z^2-1)/(2zsqrtz)`.