Question

How do you find the derivative of `f(x)= (2x^2-x+1)/(2x-1)` using the quotient rule?

Answer 1

`y'=(4x^2-4x-1)/(2x-1)^2`.

Explanation:

In this way:

`y'=((4x-1)(2x-1)-(2x^2-x+1)*2)/(2x-1)^2=`

`=(8x^2-4x-2x+1-4x^2+2x-2)/(2x-1)^2=`

`=(4x^2-4x-1)/(2x-1)^2`.