How do you solve #4v-5(3v+10) = 126#?

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Answer 1 · 2015-06-15T13:15:51

Distribute the #-5#, isolate and combine the variables on one side, and divide both sides by the coefficient of #v#. This gives #v=-16#.

#4v-5(3v+10)=126#

Distribute the #-5#.

#4v-15v-50=126#

Add #50# to both sides of the equation, and combine the #v# terms.

#-11v=176#

Divide both sides by #-11#.

#v=176/(-11)=-16#

#v=-16#