Question

How do you find the intercepts for `f(x) = 2x^2 - 5x -3`?

Answer 1

Given your function `y=f(x)`
y-inercept: `x=0, y=-3`
x-intercept: `x_1=3, y=0`
and `x_2=-1/2, y=0`

Explanation:

First you set `x=0` into your equation and get `y=f(0)=-3`.
Second you set `y=0` and solve the quadratic equation:
`2x^2-5x-3=0` using the Quadratic Formula:
`x_(1,2)=(5+-sqrt(25+24))/4=(5+-7)/4=`
`x_1=12/4=3`
`x_2=-2/4=-1/2`