How do you evaluate [4-(7-5(2-3)+2]+3?

1 Answer
Jun 23, 2015

ops...there is one bracket missing!!! I'll try two configurations:

Explanation:

1] After 2: [4-(7-5(2-3)+2color(red)(->))]+3=

[4-(7-5(2-3)+2)]+3=
I would try with this:
Bracket:
=[4-(7-5color(red)((2-3))+2)]+3=
=[4-(7-5color(red)((-1))+2)]+3=
Now multiplication (inside the bracket):
=[4-(7-color(blue)(5(-1))+2)]+3=
=[4-(7+5+2)]+3=
and solve inside the bracket:
=[4-14]+3=-10+3=-7

2] After 3: [4-(7-5(2-3)color(red)(->))+2]+3=

[4-(7-5(2-3))+2]+3=
almost as before BUT...!!!
=[4-(7-5(-1))+2]+3=
=[4-(7+5)+2]+3=
=[4-12+2]+3=
=-6+3=-3 !!!!!