Question

How do you solve `2x² - 5x - 12 = 0`?

Answer 1

I found:
`x_1=4`
`x_2=-6/4=-3/2`

Explanation:

You can use the Quadratic Formula:
`x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`
Your equation can be written in the general form:
`ax^2+bx+c=0`
Where:
`a=2`
`b=-5`
`c=-12`
So using these values in the Quadratic Formula you get:
`x_(1,2)=(5+-sqrt(25+96))/4=(5+-11)/4=`
`x_1=4`
`x_2=-6/4=-3/2`