Question

How do you solve the equation: `2x^2+15x=0`?

Answer 1

`x=0` or `x=-15/2`

Explanation:

factor the left side of `2x^2+15 =0` to get
`color(white)("XXXX")` `(x)(2x+15)=0`

Either
`color(white)("XXXX")` `x=0`
or
`color(white)("XXXX")` `2x+15 = 0`
`color(white)("XXXX")`which would imply
`color(white)("XXXX")` `color(white)("XXXX")` `x=-15/2`