How do you solve $∣ ∣ ∣ 3 - \frac{3}{4} x ∣ ∣ ∣ = \frac{1}{4}$ $abs(3 - 3/4x) = 1/4$ ?

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Answer 1 · 2015-06-28T04:27:11

Separate solving in 2 parts:

$(3 - \frac{3 x}{4}) = \frac{1}{4}$ $(3 - (3x)/4) = 1/4$ --> 12 - 3x = 1 -> 3x = 11 --> $x = \frac{11}{3}$ $x = 11/3$

2. $- (3 - \frac{3 x}{4}) = \frac{1}{4}$ $-(3 - (3x)/4) = 1/4$ -> - 12 + 3x = 1 -> 3x = 13 -> $x = \frac{13}{3}$ $x = 13/3$

How do you solve ∣∣∣3−34x∣∣∣=14abs(3 - 3/4x) = 1/4?