How do you solve #18u^2-3u=1#?
2 Answers
Explanation:
Method 1
Solutions for
can be determined using the quadratic formula (see bottom, if you don't know this formula).
or
Method 2
If we recognize that (after moving the 1 to the left side) we can factor:
to get
Then either
or
Factor
Explanation:
I use the new AC Method (Google, Yahoo Search)
Converted
Factor pairs of (-18)--> (-2, 9)(-3, 6). This sum is 3 = -b
p' = 3 and q' = - 6
Factored form: y = 18(x + 1/6)(x - 1/3) =