How do you solve #6m^2 = 13m + 28#?
1 Answer
Jun 28, 2015
Solve
Explanation:
I use the new Transforming Method (see Google or Yahoo Search).
Transformed equation:
Factor pairs of (ac = - 168) -> (6, 28)(-8, 21). This sum is 13 = -b.
The 2 real roots of (2) are: X1 = -8 and X2 = 21.
Back to original equation (1), the 2 real roots are: