How do you solve the system # x-y=11# and #2x+y=19#?

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Answer 1 · 2015-06-30T04:03:21

The solutions are:
#color(blue)(x=10#

# color(blue)(y=-1#

#x-color(blue)(y) = 11#..........equation #(1)#
#2x +color(blue)(y )= 19#........equation #(2)#

Solving by elimination

Adding the two equations will eliminate #color(blue)(y#

#x-cancelcolor(blue)(y) = 11#
#2x +cancelcolor(blue)(y )= 19#

#3x = 30#
#color(blue)(x=10#

Now finding #y# from equation #(1)#

#y = x-11#
# y =10-11#
# color(blue)(y=-1#