Question

How do you solve `3n^2 + 12n - 288 = 0`?

Answer 1

Solve `y = 3x^2 + 12x - 288 = 0`
2 real roots are: 8 and -12.

Explanation:

`y = 3(x^2 + 4x - 96) = 3g(x) = 0`. Solve g(x)
Find 2 numbers knowing sum (-4) and product (-96). Roots have different signs.
Factor pairs of (-96) --> ...(-6, 16)(-8, 12). This sum is 4 = b. Then the 2 real roots of g(x) are: 8 and -12.