How do you solve the system using the elimination method for -3x+2y=-6 and 2x+2y=5?

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Answer 1 · 2015-07-02T13:23:30

The solution is:
# color(blue)(x=11/5#
#color(blue)( y=3/10#

# -3x+color(blue)(2y)=-6 #.......equation #(1)#

#2x+color(blue)(2y)=5#............equation #(2)#

Subtracting equation #(2)# from #(1)# to eliminate #color(blue)(2y#

# -3x+cancelcolor(blue)(2y)=-6 #
#-2x-cancelcolor(blue)(2y)=-5#

#-5x = -11#
# color(blue)(x=11/5#

Finding #y# from equation #1#

# -3x+2y=-6 #

# 2y=-6 +3x #

# y=(-6 +3x )/2#

# y=(-6 +3 * (11/5) )/2#

# y=(-30 +33 )/(5 * 2#

#color(blue)( y=3/10#