Question

How do you solve `5x + 4x^2 – 4 = 0` using the quadratic formula?

Answer 1

Solve y = 4x^2 + 5x - 4 = 0

Explanation:

`D = d^2 = b^2 - 4ac = 25 + 64 = 89 --> d = +-sqrt89`

`x = (-b/(2a)) +- d/(2a) = - 4/10 +- (sqrt89)/10`