How do you find the zeroes for #y=(x+5)^2#?
1 Answer
Jul 8, 2015
There is a double root (zero) at x=-5
Explanation:
You have the equation factorised, it's trivial to see plugging in x=-5 results in y=0. The root is a double one because of the squared term, meaning the derivative (dy/dx - if you have reach calculus yet) is also zero at that point.
