Question

How do you solve `x^2+8x=12` using the quadratic formula?

Answer 1

`x ={-4+2sqrt(7) , -4-2sqrt(7)}`

Explanation:

The equation is `x^2-8*x-12=0`
The quadratic equation is:
`x =( -b +- sqrt(b^2-4*a*c)) / (2*a)`
Here, a = 1, b = 8, c = -12
Substituting these values,

`x = (-8 +- sqrt((-8)^2 + 48)) / (2*1) = (-8 +- sqrt(112)) / 2 = -4+-2sqrt(7)`

Thus the answer is `x ={-4+2sqrt(7) , -4-2sqrt(7)}`