How do I find the x-intercepts of the graph of $y = x^{2} - 3 x - 10$ $y=x^2-3x-10$ ?

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Answer 1 · 2015-07-09T18:44:44

You set $y = 0$ $y = 0$ and solve for $x$ $x$ .

$y = x^{2} - 3 x - 10 = 0$ $y = x^2-3x-10 = 0$

$(x - 5) (x + 2) = 0$ $(x-5)(x+2) = 0$

$x - 5 = 0$ $x-5 = 0$ or $x + 2 = 0$ $x+2 = 0$

$x = 5$ $x = 5$ or $x = - 2$ $x = -2$

The $x$ $x$ -intercepts are at ( $5, 0$ $5,0$ ) and ( $- 2, 0$ $-2,0$ ).

How do I find the x-intercepts of the graph of y=x^2-3x-10y=x2−3x−10y=x^2-3x-10?