How do you find the x and y-intercept given #y=-2x+5#?

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Answer 1 · 2015-07-11T21:28:26

#(0, 5), (5/2, 0)#

#x = 0 \Rightarrow y = -2 * 0 + 5#

#y = 0 \Rightarrow 0 = -2x + 5 \Rightarrow (0 - 5) / (-2) = x#

Answer 2 · 2015-07-11T21:42:26

(a). 5

(b). 5/2

#y=-2x+5#

A straight line graph is of the form:

#y=mx+c#

#m# = the gradient

#c# = the intercept which cuts the y axis

You can get this by setting #x# = 0

So #y=-2xx0+5=5#

So #c=5# which is the #y# intercept.

We can get the #x# intercept by setting #y=0#:

#0=-2x+5#

#2x=5#

#x=5/2#