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How do you solve $sin 2 x - 1 = 0$ $sin2x - 1 = 0$ from [0,360]?

1 Answer

Arunraju Naspuri

Jul 12, 2015

$x = 45^{\circ}$ $x=45^@$

Explanation:

$sin 2 x - 1 = 0$ $sin2x-1=0$

$sin 2 x = 1$ $sin2x=1$

$sin 2 x = {sin 90}^{\circ}$ $sin2x=sin90^@$

$2 x = 90^{\circ}$ $2x=90^@$

$x = 45^{\circ}$ $x=45^@$

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