Question

How do you divide `2n^2 - 3n - 1` by `2n - 5`?

Answer 1

`(2n^2 -3n -1)/(2n-5) = n + 1 - 4/(2n-5)`

Explanation:

You use the process of long division.

So,

`(2n^2 -3n -1)/(2n-5) = n + 1 - 4/(2n-5)`

Check:

`(2n-5)(n+1+4/(2n-5)) = (2n-5)(n+1) + 4 = 2n^2 -3n -5 +4 = 2n^2 - 3n - 1`