Question

How do you find the coordinates of the terminal points corresponding to the following arc length on the unit circle: -25π/6?

Answer 1

Find coordinates of terminal arc `x = (-25pi)/6`
Answers:
`x = (sqrt3)/2`
`y = - 1/2`

Explanation:

`(-25pi)/6 -> (-pi/6 - 24pi/6) -> (-pi/6 - 4pi) -> ( -pi/6)`

The terminal M of the arc `x = (-25pi)/6` has as coordinates:

`x = cos (-pi/6) = cos (pi/6) = (sqrt3)/2`

`y = sin (-pi/6) = -sin (pi/6) = - 1/2`