Question

How do you solve `4^(x+4) = 8^x`?

Answer 1

I found: `x=8`

Explanation:

You can write it as:
`(2^2)^(x+4)=(2^3)^x`
`2^(2(x+4))=2^(3x)` take the `log_2` on both sides to get rid of the `2` (where you have `cancel(log_2)(cancel(2)^x)=x`) and get:
`2(x+4)=3x`
`2x+8=3x`
`x=8`