Question

How do you solve `sin (θ/2) = √3/2` from `[0,2pi]`?

Answer 1

Solve `sin x/2 = sqrt3/2` `(0, 2pi)`

Ans: `(2pi)/3 and (4pi)/3`

Explanation:

Trig table gives ->`sin x/2 = sqrt3/2` --> `x/2 = (pi)/3` -> `x = (2pi)/3`

Trig unit circle gives another `x/2 = (2pi)/3`-> `x = (4pi)/3`