How do you find the average rate of change for the function f(x) = 4x^3 - 8x^2 - 3 on the indicated intervals [-5,2]?

1 Answer
Jul 25, 2015

The average rate of change for the function f(x) = 4x^3 - 8x^2 - 3 on the interval [-5,2] is (Deltaf)/(Deltax) = 100

Explanation:

The average rate of change of function f on interval [a,b] is:

(Deltaf)/(Deltax) = (f(b)-f(a))/(b-a)

In this case, we have a=-5, abd b = 2, so we get:

(Deltaf)/(Deltax) = (f(2)-f(-5))/(2-(-5))

= (-3-(-703))/7

= 700/7 = 100