How do you solve #5z+16=51#? Algebra Linear Equations Two-Step Equations and Properties of Equality 1 Answer Meave60 Jul 26, 2015 #z=7# Explanation: #5z+16=51# Subtract #16# from both sides of the equation. #5z=51-16# = #5z=35# Divide both sides by #5#. #z=35/5# = #z=7# Answer link Related questions How do you solve two step equations? How do you check solutions to two step equations? What is an example of a two step equation with no solution? How do I check to see if the solution is 1 for the equation #2x+1=3#? Is there more than one way to solve a 2 step equation? How do you solve #-m+3=3#? How do you solve #-5y-9=74#? How do you solve #5q - 7 = \frac{2}{3}#? How do you solve #0.1y + 11 =0#? How do you solve #\frac{5q-7}{12} = \frac{2}{3}#? See all questions in Two-Step Equations and Properties of Equality Impact of this question 1733 views around the world You can reuse this answer Creative Commons License