Question

What are the possible number of positive real, negative real, and complex zeros of `y= (2-x)(3-2x)`?

Answer 1

I found two:
`x=2`
`x=3/2`

Explanation:

If you set `y=0` you get:
`(2-x)(3-2x)=0`
this is tru when:
`2-x=0` or `x=2`
and
`3-2x=0` or `x=3/2`
these are the zeros of your function.