Question

How do you simplify `(6x-3)/5 div (4x-8)/25`?

Answer 1

`(15(2x-1))/(4(x-2))`

Explanation:

`(6x-3)/5 div (4x-8)/25`

`color(white)("XXXX")` `= (6x-3)/5 xx 25/(4x-8)`

`color(white)("XXXX")` `= (6x-3)/cancel(5) xx cancel(25)^5/(4x-8)`

`color(white)("XXXX")` `=(15(2x-1))/(4(x-2))`