How do you solve #2/3n - 7 = 19#?

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Answer 1 · 2015-08-05T13:47:46

#color(blue)(n=39#

#2/3n−7=19#

#(2n−21)/3=19#

#2n−21=19*3#

#2n=57 +21#

#2n=78#

#n=78/2#

#color(blue)(n=39#

Answer 2 · 2015-08-05T13:50:05

You isolate #n# on one side of the equation to get #n=39#.

All you need to do in order to solve this equation is get #n# alone on one side of the equation.

To do that, start by adding #7# to both sides of the equation

#2/3n - color(red)(cancel(color(black)(7))) + color(red)(cancel(color(black)(7))) = 19 + 7#

#2/3n = 26#

Now multiply boh sides of the equation by #3/2# to get

#color(red)(cancel(color(black)(3/2))) * color(red)(cancel(color(black)(2/3))) n = 26 * 3/2#

#n = color(green)(39)#