Question

How do you solve `x^2-5x+6=0` by factoring?

Answer 1

Since the `6` has a `+`-sign you're looking for two factors of `6` that add up to `-5`

Explanation:

These can only be `-2and-3` so the factoring goes:
`(x-2)(x-3)=0->x=2orx=3`