Let $f (x) = - 4 x + 3$ $f(x)= -4x+3$ and $g (x) = \frac{1}{x + 2}$ $g(x)= 1/(x+2)$ , how do you evaluate f(g(x)) and g(f(x)) for x?

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Answer 1 · 2015-08-07T12:51:10

Redefine the equations as follows:

$g (f (x)) = \frac{1}{f (x) + 2} = \frac{1}{5 - 4 x}$ $g(f(x))=1/(f(x)+2)=1/(5-4x)$

$f (g (x)) = - 4 g (x) + 3 = 3 - \frac{4}{x + 2}$ $f(g(x))=-4g(x)+3=3-4/(x+2)$

You can then evaluate the new functions using these definitions.

Let f(x)=−4x+3 f(x)= -4x+3 and g(x)=1x+2g(x)= 1/(x+2), how do you evaluate f(g(x)) and g(f(x)) for x?