Question

How do you solve `b^2 + 5b - 35 = 3b` by factoring?

Answer 1

Solve `y = b^2 + 5b - 35 = 3b`

Ans: `(b - 5)(b + 7)`

Explanation:

`y = b^2 + 2b - 35 = 0`
Find 2 numbers p and q knowing sum (b = 2) and product (c =-35).
p and q have opposite signs (Rule of signs)
Factor pairs of (-35) -->...(-1, 35) (-5, 7). This sum is 2 = b.
Then p = -5 and q = 7.

Factored form:`y = (b - 5)(b + 7)`