How do you graph and find the discontinuities of #y=(3x) /( 4-x^2)#?

1 Answer
Aug 7, 2015

For discontinuities you first look at the denominator.

Explanation:

That can be factorised into #(2-x)(2+x)#

So #x=2orx=-2# will make the denominator #=0# and are not allowed.
Also the function will come to look like #-3/(4x)# as the #4# will make less and less difference as #x# grows larger, or:

#lim_(x-> oo)=0and lim_(x-> -oo)=0#
graph{3x/(4-x^2) [-16.02, 16.01, -8.01, 8.01]}