Question

How do you solve `x^2-4x-2=0`?

Answer 1

`x=2+-sqrt(6)`

Explanation:

Complete the square for `x`:
`x^2-4x-2=(x-2)^2-6=0`

Then rearrange to make `x` the subject:
`x-2=+-sqrt(6)=>x=2+-sqrt(6)`