Question

What is the solution set for `x^2 + 6x + 10 = 0`?

Answer 1

`x =(-6+ sqrt( - 4))/ (2)`
`x =(-6- sqrt( - 4))/ (2)`

Explanation:

Since ------- `6^2` - `(4 xx1 xx 10)` < 0, x has imaginary roots

`x =(-b+- sqrt(b^2 - (4ac)))/ (2a)`
`x =(-6+- sqrt(6^2 - (4xx1xx10)))/ (2xx1)`
`x =(-6+- sqrt(36 - 40))/ (2)`
`x =(-6+ sqrt( - 4))/ (2)`
`x =(-6- sqrt( - 4))/ (2)`