What is the solution set for x^2 + 6x + 10 = 0?

1 Answer
Nallasivam V
Aug 10, 2015

x =(-6+ sqrt( - 4))/ (2)
x =(-6- sqrt( - 4))/ (2)

Explanation:

Since ------- 6^2 - (4 xx1 xx 10) < 0, x has imaginary roots

x =(-b+- sqrt(b^2 - (4ac)))/ (2a)
x =(-6+- sqrt(6^2 - (4xx1xx10)))/ (2xx1)
x =(-6+- sqrt(36 - 40))/ (2)
x =(-6+ sqrt( - 4))/ (2)
x =(-6- sqrt( - 4))/ (2)

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