#2 cos^2 x = 3 sin x# #2 (1 - sin^2 x) = 3 sin x# #2 - 2 sin^2 x = 3 sin x# #2 sin^2 x + 3 sin x - 2 = 0# #(2 sin x - 1)(sin x + 2) = 0# #sin x = -2# (no solutions) or #sin x = 1/2 \Rightarrow x = pi/6 + 2kpi=pi/6(1+12k), k in ZZ# or #x=(5pi)/6+2kpi=pi/6(5+12k), k in ZZ# #therefore x=pi/6(1+12k)# or #x=pi/6(5+12k), k in ZZ#