Question

How do you differentiate `(sinx^2)/(tanx)`?

Answer 1

`(2x cosx^2 tan x - sinx^2 sec^2 x)/ tan^2 x`

Explanation:

This can be done using quotient rule,

`(2x cosx^2 tan x - sinx^2 sec^2 x)/ tan^2 x`