How do you solve #3^(1 + 2x) = 243#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Don't Memorise Aug 19, 2015 #color(blue)(x=2# Explanation: #3^(1+2x) =243# #243=3^5# So, #3^(1+2x) =3^5# As bases are equal we equate the powers. #1+2x=5# #2x=5-1# #2x=4# #color(blue)(x=2# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3240 views around the world You can reuse this answer Creative Commons License