What is the solution set of #{3x-2)^(3/5) = 8#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer dani83 Aug 19, 2015 # x = 34/3 # Explanation: # (3x-2)^(3/5) = 8 # # 3x = 2 + 8^(5/3) # # x = 2/3(1+2^4) = 34/3 # Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1236 views around the world You can reuse this answer Creative Commons License