What is the domain and range of #y = - sqrt(9-x^2)#?
1 Answer
Domain:
Range:
Explanation:
In order to find the function's domain, you need to take into account the fact that, for real numbers, you can only take the square root of a positive number.
In other words, in oerder for the function to be defined, you need the expression that's under the square root to be positive.
#9 - x^2 >= 0#
#x^2 <= 9 implies |x| <= 3#
This means that you have
#x >= -3" "# and#" "x<=3#
For any value of
Now for the range. For any value of
The maximum value the expression under the radical can take is for
#9 - 0^2 = 9#
which means that the minimum value of the function will be
#y = -sqrt(9)= -3#
Therefore, the range of the function will be
graph{-sqrt(9-x^2) [-10, 10, -5, 5]}