A car driving at 41m/s hits the brakes and comes to a stop in 4.8 seconds. What was the car's acceleration during this stop?

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Answer 1 · 2015-08-22T22:37:16

#a=-8.54" "m.s^-2#

The acceleration is the rate of change of velocity.

If #u# = initial velocity

#v# = final velocity

#t# = time:

#a# = accelaration

Then:

#a=(u-v)/(t)#

#a =(0-41)/(4.8)=-8.54" "m.s^-2 #

The minus sign signifies that the car is decelerating.