How do you solve #x+y= -3# and #x+y=3#?
1 Answer
Aug 23, 2015
Explanation:
Your system of equations will have no solution.
You can think about this in two ways.
Notice that you have
#x+y = -3#
and the second equation has
#x+y = 3#
If you try to replace
#3 != -3#
An alternative approach is to notice that you're dealing with the equations of two lines. When you're solving a system of equations, you're essentially looking for the point in which those lines intersect.
In your case, these lines will never intersect because they are parralel lines.
graph{(y+x-3)(y+x+3)=0 [-10, 10, -5, 5]}