How do solve 4logx = 24.84logx=24.8?

1 Answer
Aug 29, 2015

Assuming your loglog is base 10:
4log(x) = 24.8 color(white)("XXX")rArrcolor(white)"XXX"x=15848934log(x)=24.8XXXXXXx=1584893

Explanation:

4log(x) = 24.84log(x)=24.8
rarrcolor(white)("XXX")log(x)= 24.8/4 = 6.2XXXlog(x)=24.84=6.2

In general
color(white)("XXX")log_b(x)=ycolor(white)("XXX")"means"color(white)("XXX")b^y=xXXXlogb(x)=yXXXmeansXXXby=x

So
color(white)("XXX")log_10(x)=6.2color(white)("XXX")"means"color(white)("XXX")10^(6.2) =xXXXlog10(x)=6.2XXXmeansXXX106.2=x
and (with the aid of a calculator)
color(white)("XXX")x=1584893XXXx=1584893