Question

How do solve `4logx = 24.8`?

Answer 1

Assuming your `log` is base 10:
`4log(x) = 24.8 color(white)("XXX")rArrcolor(white)"XXX"x=1584893`

Explanation:

`4log(x) = 24.8`
`rarrcolor(white)("XXX")log(x)= 24.8/4 = 6.2`

In general
`color(white)("XXX")log_b(x)=ycolor(white)("XXX")"means"color(white)("XXX")b^y=x`

So
`color(white)("XXX")log_10(x)=6.2color(white)("XXX")"means"color(white)("XXX")10^(6.2) =x`
and (with the aid of a calculator)
`color(white)("XXX")x=1584893`